Prove that the equation $x^3y^3z^33xyz=1$ defines a surface of revolution and find the analytical equation of its axis of revolution I think that I need to apply Euler's formula, so that I g Stack Exchange Network x³ y³ z³ 3xyz = (x y z) (x² y² z² – xy – yz– zx) In order to find the formula of x³ y³ z³, we need to send 3xyz to the right side of equal sign Thus the formula becomes, x³ y³ z³ = (x y z) (x² y² z² – xy – yz– zx) 3xyzIf x y z = 6, x2 y2 z2 = 16 and x3 y3 z3 = 196 Then find the value of 3xyz 1 160 2 140 3 130 4 1
U Log X 3 Y 3 Z 3 3xyz X Y Z Ux Uy Uz
X^3+y^3+z^3-3xyz formula
X^3+y^3+z^3-3xyz formula-Stack Exchange network consists of 178 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers Visit Stack Exchangeयदि x y z = 9, xy yz zx = 23, तब `x^(3) y^(3) z^(3) 3xyz=` A 100 B 81 C 108 D 123 Welcome to Sarthaks eConnect A unique platform where students can interact with teachers/experts/students to get solutions to their queries
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verify that ` x^3 y^3 z^3 3xyz = 1/2( xyz) (xy)^2 (yz)^2 (za)^2 ` Books Physics NCERT DC Pandey Sunil Batra HC Verma Pradeep Errorless Chemistry NCERT P Bahadur IITJEE Previous Year Narendra Awasthi MS Chauhan Biology NCERT NCERT Exemplar NCERT Fingertips We know that x3 y3 z3 3xyz = (x y z) (x2 y2 z2 xy yz zx) Putting x y z = 0, x3 y3 z3 3xyz = (0) (x2 y2 z2 xy yz zx) x3 y3 z3 3xyz = 0 x3 y3 z3 = 3xyz Hence proved Show MoreThe formula of x 3 y 3 z 3 – 3xyz is written as \(\begin{array}{l}x^{3} y^{3} z^{3} – 3xyz = (x y z) (x^{2} y^{2} z^{2} – xy – yz – zx)\end{array} \) Let
Click here👆to get an answer to your question ️ Factorise 27x^3 y^3 z^3 9xyzX 3 y 3 z 3 3xyz = (xy) 3 3x 2 y 3xy 2 z 3 3xyz = (xy) 3 z 3 3xy (xyz) = (xyz) (xy) 2 z (xy) z 2 3xy (xyz) = (xyz) (x 2 2xyy 2 xzyzz 2 3xy) = (xyz) (x 2 y 2 z 2 xyyzzx) bởi Nguyễn Thanh Huyền Like (1) Báo cáo sai phạm Cách tích điểm HP What must be subtracted from 4x^42x^36x^22x6 so that the result is exactly divisible by 2x^2x1?
Answer is (xy z)(x^2 y^2 xyz z^2) You can check by multiplying it out Notice that each term is a perfect cube x^3 y^3 = (xy)^3 So we have a sum of cubes, and the factoring formula is a^3 b^3 = (ab)(a^2abb^2) So we use a = xy and b = z to get x^3 y^3 z^3 = (xy)^3 z^3 = ((xy) z)((xy)^2(xy)zz^2) =(xy z)(x^2 y^2 xyz z^2) check by multiplying itGiven x y z = 8, xy yz zx = 15 Formula used x3 y3 z3 3xyz = (x y z) (x2 y2 z2 xy yz Q1 There were 1 students who went for summer camp students joind them after some time, Due to which the cost of consumption increased by Rs 80 per day and the average cost of each students decrease by RsSo,x3y3z3−3xyz =(xyz)(x2y2z2−xy−yz−zx) = (xyz)((xyz)2−3xy−3yz−3zx) = (xyz)((xyz)2−3(xyyzzx) = 9(92−3×23) = 9(81−69) = 9×12 = 108 (a) 108 Mathematics Secondary School Mathematics IX Standard IX Suggest Corrections 0
If X Y Z 0 Show That X3 Y3 Z3 3 Xyz Brainly In
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Given x y z = 0 Formula used x3 y3 z3 = {(x y z) × (x2 y2 z2 xy yz zx)} 3xyz Calculation &rA With hundreds of Questions based on Algebra, we help you gain expertise on Quantitative AptitudeAll for free Explore Testbook Learn to attain the subject expertise with usX^3y^3z^33xyz=(xyz)(x^2y^2z^2xyyzzx)a^3b^3c^33abc=(abc)(a^2b^2c^2abbcca)a^3b^3c^33abc formula proofx^3y^3z^33xyz formula proofaA) 36 b) 40 c) 42 d) 48
Prove That X Y3 Y Z3 Z X3 3x Yy Zz X 2x3 Y3 Z3 3xyz Maths Polynomials Meritnation Com
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Complete stepbystep answer Now, we will use partial differentiation It is denoted by ∂ We are given u = log (x3 y3 z3 3xyz) So, partially differentiating u with respect to x, we get ∂u ∂x = 3x2 3yz (x3 y3 z3 3xyz) Similarly, partially differentiating u with respect to y and z, we getAnswer by lenny460 (1073) ( Show Source ) You can put this solution on YOUR website! If ${ax by cz =1}$, then show that in general ${x^3 y^3 z^3 3xyz}$ has two stationary values ${0}$ and $\frac{1}{(a^3b^3c^33abc)}$, of
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Given (xyz) = 9∴ (x y z)2 = 92 = 81∴ x2 y2 z2 2 × 26 = 81∴ x2 y2 z2 = 81 52 = 29Now, x3 y3 z3 3xyz= (x y z) (x2 y2 z2) (xyFind the value of x3 y3 z3 3xyz if x y z 12 and x2y2z270 Hint Here, we have to find the value of the algebraic expression We will find the value of the sum of the product of the variables by substituting the given equation in the square of the sum of the three variables' identityThere are two formula of it 1 x^3 y^3 z^3 3xyz = (xyz) (x^2y^2z^2xyyzzx) 2 x^3 y^3 z^3 3xyz = (1/2) (xyz) {xy)^2(yz)^2(zx)^2}
If X Y Z 0 Then Prove That X3 Y3 Z3 3xyz Youtube
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There are two formula of it 1 x^3 y^3 z^3 3xyz = (xyz) (x^2y^2z^2 xyyzzx) (xyz)(x^2y^2z^2xyyzxz) Stepbystep explanation and plz follow meConsider (x – y – z) 2 ⇒ x 2 (y 2) (z 2) 2 x (y) 2 (y) (z) 2 (z) x ⇒ (x – y – z) 2 = x 2 y 2 z 2 – 2xy – 2xz 2yz Let us prove the above equation Consider x = 2, y = 3 and z = 4 Substitute in the above equation we get LHS = (x – y – z)X y z = 2 x 3 y 3 z 3 3xyz = 74 Formula used a 3 b 3 c 3 3abc = (a b c)/2 3(a 2 b 2 c 2) (a b c) 2 Calculation According to the formula 2/2 3(x 2 y 2 z 2) 2 2 = 74 ⇒ 3(x 2 y 2 z 2) = 74 4 ⇒ x 2 y 2 z 2 = 78/3 = 26 ∴ Required answer is 26
If X Y Z 0 Then Show That X3 Y3 Z3 3xyz If X Y Z 0 Prove That X3 Y3 Z3 3xyz Youtube
Ex 2 5 11 Factorise 27 X3 Y3 Z3 9xyz Class 9 Ex 2 5
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